If (x+2) and (x-2) are factors of (ax)4+2x−3x2+bx−4 then find the value of a+b? pls answer
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Answer:
Case- 1
X+2=0
X=-2 put in the 4ax +2x-6x+bx-4
- -8a-4+12-2b-4
- -8a+4-2b=0
- 8a+2b-4=0
- 8a+2b=4
4a+b=2 equation (I)
Case-2
x-2=0 ,X=2 put in the 4ax +2x-6x+bx-4
- 8a+4-12+2b-4
- 8a-12+2b=0
4a+b=6 equation(ii)
From equation (I) and(ii) we get
Hence prove that your question is wrong.
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