If x=2 and x =3/4 are the solution to the equation px2+qx-6=0 find the value of p and q
Answers
Answer:
if x = 2
px^2 + qx + 6 = 0
p(2)^2 + 2q + 6 = 0
4p + 2q + 6 = 0.........(i)
if x = 3/4
px^2 + qx + 6 = 0
p(3/4)^2 + q(3/4) + 6 = 0
p(9/16) + 3q/4 + 6 = 0
9p/16 + 12q/16 + 96/16 = 0
9p+12q+96/16 = 0 16 is in the denominator so it
9p + 12q + 96 = 0 ........ (ii) will multiply with 0 = 0*16
= 0
(i) eqn * 6
24p + 12q + 36 = 0
24p + 12q + 36 = 0
-9p + 12q + 96 = 0
....................................
15 p - 60 = 0
...................................
15p - 60 = 0
15p = 60
p = 4
4p + 2q + 6 = 0
4(4) + 2q + 6 = 0
16 + 2q + 6 = 0
32 + 2q = 0
2q = -32
q = -16
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