if x=2 and x =3 are roots of the equation 3x^2-2ax+2b=0 then find the value of a and b
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Ques. 3x²-2ax+2b=0
alpha=2 , beata= 3
alpha +beata = -b/a
2+3= - (-2a)/3
5×3 = 2a
15/2=a
alpha×beata= c/a
2×3 = 2b/3
6×3 = 2b
18/2=b
9 = b
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