if x=2 and x=3 are roots of the equation 3x^2_2kx_2m=0,find the value of k and m.
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When x= 2
3(2)^2 - 2k(2) - 2m=0
12 - 4k - 2m=0
-4k-2m=12
-2(2k +m)= - 12
2 k +m=6 eq 1
When x=3
3(3)^2 - 2k(3) - 2m
27 - 6k - 2m = 0
-6k - 2m =-27
-2(3k+m) =-27
3k+m = 13.5
2k + m = 6
3k + m = 13.5
- - -
- k = - 7.5
K = 7.5
2k + m = 6
15 +m =6
M = - 9
3(2)^2 - 2k(2) - 2m=0
12 - 4k - 2m=0
-4k-2m=12
-2(2k +m)= - 12
2 k +m=6 eq 1
When x=3
3(3)^2 - 2k(3) - 2m
27 - 6k - 2m = 0
-6k - 2m =-27
-2(3k+m) =-27
3k+m = 13.5
2k + m = 6
3k + m = 13.5
- - -
- k = - 7.5
K = 7.5
2k + m = 6
15 +m =6
M = - 9
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