Question

if x=2 and x=3 are roots of the equation
$3 {x}^{2} - 2ax + 2b = 0$
then find the value of a and b​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

if,

x=2,3

3x²-2ax+2b=(x-2)(x-3)

=>(x-2)(x-3)

x²-2x-3x+6

x²-5x+6=0

multiply with 3 on both sides

3(x²-5x+6)=0*3

3x²-15x+18=0

by comparing with given equation,

a=15/2,b=18

hope it helps you

Mark as brainliest...