Question

If (x-2) and (x+3) are the factors of p(x)= ax³ + 3x³ -bx - 12. Find the value of 'a' and 'b'.​

Answer 1

Answer:

a=1 , b=4

Step-by-step explanation:

explanation is attached

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Answer 2

Step-by-step explanation:

x-2=0

x=2

p( x)= ax³+3x³-bx-12

p(2) =a( 2 )³+3( 2 )³-b× 2-12

=8a+24-2b-12

=8a-2b+12

so, 8a-2b+12=0

8a=2b-12

a={2b-12}/8. let's be 1st equation

x+3=0

x=-3

p(x)=ax³+3x³-bx-12

p(-3)=a(-3)³+3(-3)³-b(-3)-12

= -27a - 71+3b -12

=-27a+3b-83

So, -27a+3b-83=0

-(27a-3b+83)=0

27a-3b+83=0

27a=3b-83

a= {3b-83}/27. 2nd equation.

Now ,

Comparing eq. 1 and 2

(2b-12)/8 = (3b-83)/27

Cross multiple

And u will get the value of , b

Then at last u will put the value of , b in any equation then u will get the value of , a.

I think this will help you