if x=_2 and x=3 are the solutions of the quadratic equation 3x square-2kx+2m=0.Find the value of k and m
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Adding to the answers already given , this problem is solved with the help of a CAS such as Mathematica by typing the following code :
sol = Solve[3 x^2 - 2 k x + 2 m == 0, x];Solve[2 == sol[[1, 1, 2]] && 3 == sol[[2, 1, 2]], {k, m}]
The result or answer obtained is :
k=152k=152 and m=9m=9 .
For a more general equation of the form
ax2+bkx+cm=0ax2+bkx+cm=0 with roots x1x1 and x2x2 ,
the solution is :
k=−a(x1+x2)bk=−a(x1+x2)b and m=ax1x2cm=ax1x2c .
ibadarbaz23:
wrong
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