Math, asked by michimanu978, 15 days ago

if x=-2 and x=3 are the solutions of the quadratic equation 3x²-2kx+2m=0,find the values of k and m​

Answers

Answered by devyanshgurjarcentra
2

Answer:

x = 2 is a root of given equation substitute x = 2 in L.H.S.

L.H.S. = 3(2)2 – 2k × 2 + 2m = 0

12 – 4k + 2m = 0

4k – 2m = 12 …(i)

Similarly when x = 2 is root of given equation

Substitute x = 3 in L.H.S.

L.H.S. = 3(3)2 – 2k × 3 + 2m = 0

27 – 6k + 2m = 0

6k – 2m = 27 …(ii)

On solving equations (i) and (ii), we get

k = 15/2 and m = 9

Step-by-step explanation:

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