if X + 2 and X + 3 arefactor of a x cube + a x + b find the value of a and b
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∴x=1 ⇒2 ∴x=2 ⇒3
substitution eqn2 in eqn1 we get,
(1)³-a(1)+b=0
1-a+b=0
a=1+b ⇒4
substituting eqn3 in 1 we get
(2)³-a(3)+b=0
8-3a+b=0 ⇒5
substituting eqn4 in eqn5 we get,
8-3(1+b)+b=0
8-3-3b+b=0
2b=5
b=5/2
a= 1+b= 1+5/2
a=7/2
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