if X + 2 and x minus 1 are the factors of x cube + 10 X square + m into X + n then the value of M and n are respectively what
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as x+2 and ×-1 are roots of the equation there fore x= -2 or x=1 should satisfy the equation and it should be zero
by putting x= -2 in the given equation
x^3+10x^2+mx+n , we get
-8+40-2m+n=0
n=2m-32 (1)
putting x=1 in the given equation
we get
1+10+m+n=0
n+m+11=0
from (1) substituting the value of n
2m-32+m+10=0
m-22=0
m=22
therefore from (1) n=2×(22) - 32
n=44 - 32
n= 10
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