If (x-2) and (x plus 3) are factors of p (x) is equal to ax ka Cube + 3 x square - BX - 12 find the value of a and b
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Step-by-step explanation:
ax^3+3x^2-Bx-12 is the equation
x=2,-3 are the zeroes
then substitute in equation
at x=2
8a+12-2B-12=0------(1)
B=4a----[1]
x= -3
-27a+27+3B-12------(2)
substitute [1] in (2)
-27a+15+12a=0
15a=15
a=1
then B =4
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that is a right answer of polynomial topic Factor therum
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