Question

if x=-2 and x²+y²-3x y²-5 then find y
need steps by step ​

Answer 1

$put \: value \: of \: x = 2 \: to \: find \: the \: value \: of \: y \: \\ {x}^{2} + {y}^{2} - 3x {y}^{2} - 5 \\ \\ solve = > ({2)}^{2} + {y}^{2} - 3 \times 2 \times {y}^{2} - 5 \\ \\ = > 4 + {y}^{2} - 6 {y}^{2} - 5\\ \\ = > - 5 {y}^{2} - 1 = 0 \\ \\ = > - 5 {y}^{2} = 1 \\ \\ = > {y}^{2} = \frac{1}{ - 5} \\ \\ = > y = \sqrt{ \frac{1}{5} } \\ \\ = > y = \frac{1}{ \sqrt{5} } \:$