Question

if x= -2 and y= 2 find the value of 1. (x^3)^2+xy^2+2x
2. 6x^-3+4y^3​

Answer 1

Answer:

1. 0

2. 31.25

Step-by-step explanation:

$1. {(x^{3})}^2 + x * y^{2} + 2x \\= {(-2^{3})}^2 + ( -2) * (2)^{2} +2 (-2)\\= (-8)^{2} + (-2) * (4) -4\\= 64-2*4-4\\=62*0\\= 0$

$2. 6x^{-3} + 4y^{3}\\ = 6(-2)^{-3} + 4(2)^{3} \\= 6 (-0.125) + 4(8)\\= -0.75 + 32\\= 31.25$