Question

if x =2 and y=3, find the value (2x²y³)×(4x²y³)

Answer 1

Step-by-step explanation:

(2x²y³)×(4x²y³)

(2×2²×3³) ×(4×2²×3³)

(2×4×27)×(4×4×27)

216×432

93,312

Answer 2

SOLUTION

Given,

x= 2

y= 3

$= > (2 {x}^{2} {y}^{3} ) \times (4 {x}^{2} {y}^{3} ) \\ = > (2(2) {}^{2} (3) {}^{3} ) \times (4(2) {}^{2} (3) {}^{3} ) \\ = >( 2 \times 4 \times 27) \times (4 \times 4 \times 27) \\ = > 216 \times 432 \\ = > 93312$

hope it helps ☺️