if x= 2 and y=3 is a solution of (p+1) x- (2p+3) y-1 find the value of p
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x=2 ,y=3
(p+1)2 - (2p+3)3 - 1=0
2p+2- (6p+9) -1=0
2p+2-6p-9-1=0
-4p-8=0
-4p=8
p=-2
(p+1)2 - (2p+3)3 - 1=0
2p+2- (6p+9) -1=0
2p+2-6p-9-1=0
-4p-8=0
-4p=8
p=-2
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