if X=2 and y=4 then find [x/y]^x-y+[y/x]^y-x=_____.
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=[2/4]^2-4+[4/2]^4-2
=[1/2]^2-4+[2]^4-2
=[1/4]-4+16-2
=(1/4)-10+2
=(1/4)-8
=(-8/4)
=-2
HOPE THIS WILL HELP YOU OUT.......
=[1/2]^2-4+[2]^4-2
=[1/4]-4+16-2
=(1/4)-10+2
=(1/4)-8
=(-8/4)
=-2
HOPE THIS WILL HELP YOU OUT.......
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