if x-2 and2x-1 are factors of px^2+5x+r show that p=r
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Given that (x - 2) and (2x - 1) are factors,
So, x - 2 = 0 and 2x - 1 = 0
x = 2 and x = 1/2
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Putting x = 2
px² + 5x + r = 0
p(2)² + 5(2) + r = 0
4p + 10 + r = 0
4p + r = -10 -------1equation
------------------------------
Putting x = 1/2
p(1/2)² + 5(1/2) + r = 0
p/4 + 5/2 + r = 0
(p + 4r)/4 = -5/2
p + 4r = -10 ----------2equation
==============================
4p + r = -10
p + 4r = -10
As both are equal to -10
then ,equations are equal
4p + r = p + 4r
3p - 3r = 0
3(p - r) = 0
p - r =0/3
p - r =0
p =r
Hence, proved.
i hope this will help you
(-:
So, x - 2 = 0 and 2x - 1 = 0
x = 2 and x = 1/2
=====================
Putting x = 2
px² + 5x + r = 0
p(2)² + 5(2) + r = 0
4p + 10 + r = 0
4p + r = -10 -------1equation
------------------------------
Putting x = 1/2
p(1/2)² + 5(1/2) + r = 0
p/4 + 5/2 + r = 0
(p + 4r)/4 = -5/2
p + 4r = -10 ----------2equation
==============================
4p + r = -10
p + 4r = -10
As both are equal to -10
then ,equations are equal
4p + r = p + 4r
3p - 3r = 0
3(p - r) = 0
p - r =0/3
p - r =0
p =r
Hence, proved.
i hope this will help you
(-:
shanaya555:
thankz
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