Math, asked by palaky168, 5 months ago

If x^2 -aX+21= (x-7)(x-3), the value of a will be.​

Answers

Answered by pavani7562
1

Answer:

x²-ax+21=(x-7)(x-3)

x²-ax+21=x²-3x-7x+21

-ax=-10x

ax=10x

a=10

hence value of a is 10

Answered by ankushdalvi1980
0

Step-by-step explanation:

If x^2 -aX+21= (x-7)(x-3), the value of a will be.

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