Question

if(x-2)be a factor of tge polynomial p(x)=2x³+3x²-5x+k,find the value of k​

Answer 1

Answer:

k=18

Step-by-step explanation:

p(x)=2x3+3x2-5x+k

= 2(2)3+3(2)2-5(2)+k

k=2(8)+3(4)-5(2)

k=16+12-10

k=18

Answer 2

g(x)=x-2=0

x=2

p(x)= 2x^3+3x^2 -5x+k=0

2(2)^3+3(2)^2-5(2)+k=0

16 +12 -10 +k=0

28 -10+k=0

18+k=0

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k =-18