if x= 2 cm and y=0 the area of square is equal to
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Step-by-step explanation:
The equation of the given lines are
y-x = 0....(1)
x + y =...(2)
x - k = 0...(3)
The point of intersection of lines (1) and (2) is
given by
x = 0 and y = 0
The point of intersection of lines (2) and (3) is
given by
x = k and y = -k
The point of intersection of lines(3) and (1) is given
by
x = k and y = k
Thus, the vertices of the triangle formed by the three given lines are (0, 0), (k, -k), and (k, k)
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We know that the area of the triangle whose
vertices are (x₁, y₁), (x2, y2), and (x3, y3) is 1 | X1(Y2 - Y3) + X2(Y3 - Y₁) + X3(y₁ - y2) |
2
Therefore, area of the triangle formed by the three given lines,
1 2 = | 0(-k-k) + k(k - 0)+k(0+ k) square unts
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1 k² +k² square units
1 2 = |2k²| = k² square units
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