If (x-2) divides x^3-3x^2+k exactly . Find the value of k
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Answer:
let f(x)=0
f(x)= (x-2)
x-2=0
x=2
now putting x=2 in given equation
x³-3x²+k=0
(2)³-3(2)²+k=0
8-12+k=0
k-4=0
k=4
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