If x=
2 {}^{ \frac{1}{2} } + 2 ^{ \frac{2}{3} }221+232
show that
{x}^{3} - 6x = 6x3−6x=6
Answers
Answered by
1
x^3 -6x=6×3 -6x=6
or, x^3=18-6x=6
or, x^3=12x=6
or, x^3-6+12=0
or, x^3- (3x+4x) +12=0
or, x(x^2-3)+ 4(x^2-3) =0
or, (x^2-3 ) (x+4)
Answered by
2
Answer:
x^3 -6x=6×3 -6x=6
or, x^3=18-6x=6
or, x^3=12x=6
or, x^3-6+12=0
or, x^3- (3x+4x) +12=0
or, x(x^2-3)+ 4(x^2-3) =0
or, (x^2-3 ) (x+4)
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