Math, asked by poonianaresh78p3767p, 10 months ago

If x=
2 {}^{ \frac{1}{2} } + 2 ^{ \frac{2}{3} }221​+232​
show that
{x}^{3} - 6x = 6x3−6x=6​

Answers

Answered by Anonymous
1

x^3 -6x=6×3 -6x=6

or, x^3=18-6x=6

or, x^3=12x=6

or, x^3-6+12=0

or, x^3- (3x+4x) +12=0

or, x(x^2-3)+ 4(x^2-3) =0

or, (x^2-3 ) (x+4)

Answered by SelieVisa
2

Answer:

x^3 -6x=6×3 -6x=6

or, x^3=18-6x=6

or, x^3=12x=6

or, x^3-6+12=0

or, x^3- (3x+4x) +12=0

or, x(x^2-3)+ 4(x^2-3) =0

or, (x^2-3 ) (x+4)

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