Question

If
{x}^{2} + \frac{1}{ {x}^{2}} = 14x
2
+
x
2

1
​
=14
Find:
(1) \: x + \frac{1}{x}(1)x+
x
1
​

(2) \: x - \frac{1}{x}(2)x−
x
1
​

(3) \: {x}^{2} - \frac{1}{ {x}^{2} }(3)x
2
−
x
2

1
​
​

Answer 1

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