Math, asked by umangbaba, 4 days ago

If x^2 - hx - 21 = 0, x^2 - hx + 35 = 0 have a common root then h is 1) +- 2 2) +- 4 3) +- 6 4) +- 8

Answers

Answered by rakeshkarri79
0

Answer:

Let be the common roots of:  

  ² – ℎ – 21 = 0  

and  

  ² – 3ℎ + 35 = 0  

Then by definition of a root, we have the system:  

  {  ² – ℎ – 21 = 0  

  {  ² – 3ℎ + 35 = 0  

► Subtracting second equation from the first yields:  

  (² – ℎ – 21) – (² – 3ℎ + 35) = 0 – 0  

  ² – ℎ – 21 – ² + 3ℎ – 35 = 0  

  ² – ² – ℎ + 3ℎ – 21 – 35 = 0  

  0 + 2ℎ – 56 = 0  

  2ℎ = 56  

  = 28/ℎ  

► Inserting this in the first equation:  

  ² – ℎ – 21 = 0  

  (28/ℎ)² – ℎ(28/ℎ) – 21 = 0    ← Since =28/ℎ  

  784/ℎ² – 28 – 21 = 0  

  784/ℎ² – 49 = 0  

  784/ℎ² = 49  

  16/ℎ² = 1                             ← Divide both sides by 49  

   16 = ℎ²                              ← Multiply both sides by ℎ²  

   ℎ = ±4  

► Now since we are told that ℎ>0, the solution ℎ=-4 is discarded leading to the final conclusion that:  

  ℎ = 4        ◄ANSWER

Step-by-step explanation:

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Answered by ruchagamergirl
1

Answer:

Now since we are told that ℎ>0, the solution ℎ=-4 is discarded leading to the final conclusion that:  

  ℎ = 4  

Step-by-step explanation:

Let be the common roots of:  

  ² – ℎ – 21 = 0  

and  

  ² – 3ℎ + 35 = 0  

Then by definition of a root, we have the system:  

  {  ² – ℎ – 21 = 0  

  {  ² – 3ℎ + 35 = 0  

► Subtracting second equation from the first yields:  

  (² – ℎ – 21) – (² – 3ℎ + 35) = 0 – 0  

  ² – ℎ – 21 – ² + 3ℎ – 35 = 0  

  ² – ² – ℎ + 3ℎ – 21 – 35 = 0  

  0 + 2ℎ – 56 = 0  

  2ℎ = 56  

  = 28/ℎ  

► Inserting this in the first equation:  

  ² – ℎ – 21 = 0  

  (28/ℎ)² – ℎ(28/ℎ) – 21 = 0    ← Since =28/ℎ  

  784/ℎ² – 28 – 21 = 0  

  784/ℎ² – 49 = 0  

  784/ℎ² = 49  

  16/ℎ² = 1                             ← Divide both sides by 49  

   16 = ℎ²                              ← Multiply both sides by ℎ²  

   ℎ = ±4  

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