If x-2 i factor of x 3 - 2ax +ax-1 the value of a is
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Answered by
1
Answer:
Step-by-step explanation:
x - 2 = 0
x = 2
f(2) = 2(3) - 2a(2) + a(2) - 1 = 0
(substituting the value of x by 2)
6 - 4a + 2a -1 =0
5 -2a = 0
-2a = -5
a = 5/2
Answered by
1
Answer:
x-2 =0
x=2
now as x-2 is the factor of x^3-2ax+ax-1
then we can write this as
= p(x) = x^3-2ax+ax-1
= p(2) = 2^3 -2×a×2 + 2×a -1
= 8-4a+2a-1
= 7-2a = 0
= a = 7/2
hope this may be helpful
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