Question

if (x-2) is a divisior of p(x) =3x2-kx+10 find the value of k​

Answer 1

Answer:

x=2

Step-by-step explanation:

p(2)=3×2^2-k×2+10

=>12-2k+10

=>22-2k

=>2k=22

=>k=22÷2

=>k=11

Answer 2

Answer

x - 2 = 0

x = 2

p(x) = 3x^2-kx+10

p(2) = 3(2)^2 - k(2) + 10 = 0

12 - 2k + 10 = 0

22 = 2k

k = 11