If (x-2) is a divisor of the polynomial p(x)=x³-2x-1 find the remainder
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The remainder when x³-2x-1 is divided by (x-2) is 3.
Given:
(x-2) is the divisor of x³-2x-1.
To Find:
The remainder.
Solution:
By the Remainder theorem,
g(x) = 0
x-2=0
x=2
Substituting the value of x=2 in x³-2x-1.
2³-2(2)-1
= 8-4-1
=8-5
=3
Therefore, the remainder when x³-2x-1 is divided by (x-2) is 3.
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