If (x-2) is a factor of 2x^2+kx-2√3, the value of k is-
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Answered by
1
Hey!!!!
We have
2x² + kx - 2√3 = 0
and x - 2 = 0
=> x = 2
Thus 2(2)² + k(2) - 2√3 = 0
=> 8 + 2k - 2√3 = 0
=> 2k = 2√3 - 8
=> k = √3 - 4
Hope this helps
We have
2x² + kx - 2√3 = 0
and x - 2 = 0
=> x = 2
Thus 2(2)² + k(2) - 2√3 = 0
=> 8 + 2k - 2√3 = 0
=> 2k = 2√3 - 8
=> k = √3 - 4
Hope this helps
gokunipu:
Thank dude
welcome
Answered by
2
X-2
X=2
2x^2+kx-2root 3
2(2)^2+k(2)-2root 3
2(4)+2k-2root3
8+2k=2root 3
2k=2root3-8
K=2root 3-8/2=2(root 3-4)/2=root 3-4
Hope it's help you friend ☺️
X=2
2x^2+kx-2root 3
2(2)^2+k(2)-2root 3
2(4)+2k-2root3
8+2k=2root 3
2k=2root3-8
K=2root 3-8/2=2(root 3-4)/2=root 3-4
Hope it's help you friend ☺️
Yes it actually helped me
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