if x-2 is a factor of 2x3-11x2+bx-6 then the value of B is
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ANSWER :–
GIVEN FUNCTION :–
2 X³ - 11 X² + bx - 6 =0
TO FIND :–
VALUE OF "b"
SOLUTION :–
=》 2 x³ - 11 x² + b x - 6 = 0 , it's one factor is (x - 2) .
● SO , THAT PUT X = 2 in EQUATION –
=》 2 (2)³ - 11(2)² + 2b - 6 = 0
=》 16 - 11 × 4 + 2b - 6 = 0
=》 16 - 44 - 6 + 2b = 0
=》 2b - 34 = 0
=》 b = 17
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