Math, asked by ashwinthreddy, 10 months ago

if x-2 is a factor of 2x3-11x2+bx-6 then the value of B is​

Answers

Answered by BrainlyPopularman
21

ANSWER :

GIVEN FUNCTION :

2 X³ - 11 X² + bx - 6 =0

TO FIND :

VALUE OF "b"

SOLUTION :

= 2 x³ - 11 x² + b x - 6 = 0 , it's one factor is (x - 2) .

SO , THAT PUT X = 2 in EQUATION

= 2 (2)³ - 11(2)² + 2b - 6 = 0

= 16 - 11 × 4 + 2b - 6 = 0

= 16 - 44 - 6 + 2b = 0

= 2b - 34 = 0

= b = 17

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