If (x+2) is a factor of 2x³+5x²-x-k then the value of k is
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Answered by
3
Answer:
6
Step-by-step explanation:
Let p( x ) = 2x³ + 5x² - x - k
x + 2 is a factor
Finding zero of (x + 2)
=> x + 2 = 0
=> x = - 2
By Factor theorem
p( - 2 ) = 0
=> 2( - 2 )³ + 5( - 2 )² - ( - 2 ) - k = 0
=> 2( - 8 ) + 5( 4 ) + 2 - k = 0
=> - 16 + 20 + 2 - k = 0
=> - 16 + 22 - k = 0
=> 6 - k = 0
=> k = 6
Answered by
2
Answer:Factor is (x+2)
Solution:
x+2=0
x= -2
Now we will solve this putting the value of x in p(x).
p(x)=0
2(-2)^3+5(-2)^2-(-2)-k=0
2(-8)+5(4)+2-k=0
-16+20+2=k
22-16=k
6=k
Hope it helps.....
Please mark it as brainliest.
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