Question

if x+2 is a factor of 3x^2 +px^2+px-1 then the value of p is

please help fast..please

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge{\mathbb{\blue{ANSWER}}}$

GIVEN:-

• (x+2) is a factor of $3x^2+px^2+px-1$

TO FIND:-

• The value of P

Now,

$x+2=0$

$x=-2$

Put the value of x in given p(x).

$p(-2)=3(-2)^2+p(-2)^2+p(-2)-1=0$

$12+4p-2p-1=0$

$11+2p=0$

$2p=-11$

$p=\huge\frac{-11}{2}$

Hence,

The value of p is$\huge\frac{-11}{2}$.

$\textbf{EXTRA\:INFORMATION}$

$(a+b)^2=a^2+2ab+b^2$

$(a-b)^2=a^2-2ab+b^2$

$a^3+b^3=(a+b) (a^2-ab+b^2)$