Question

If x-2 is a factor of 5^4-10x³+2x²-px+10 find the value of p

Answer 1

Answer:

X-2 is a factor , so put X= 2 is a root of quadratic equation.

$5 {(2)}^{4} - 10 {(2)}^{3} + 2 {(2)}^{2} - 2p + 10 = 0 \\ \\ 80 - 80 + 8 - 2p + 10 = 0 \\ \\ 2p = 18 \\ \\ p = 9$

Answer 2

Answer:

5(2)^4-l0(2)^3+2(2)^2-p(2) +10=o

80-80+8-2p+10=0

I8-2p=0

2p=18

P = 18/2=9. Ans