Math, asked by narendrasingh4935, 2 months ago

If x – 2 is a factor of 5x² – kx – 18, then find the value of k. Please give as fast as you can.​

Answers

Answered by nicksverma55
7

Answer:

p(2) =5(2)²-k(2)-18

0=20-2k-18

0=2-2k

Hence, k=-1

Answered by prasannanalla1983
17

Answer:

answer is 1

If (x - a) is a factor of p(x) = 5x² - kx - 18, then p( a) = 0

OR

p(a) = 0, where a is zero of the equation (x - a)

[ p(x) = 5x² - kx - 18]

find the zero of (x-2)

⟹ (x - 2) = 0

⟹ x = 0 + 2

⟹ x = 2

p(2) = 5(2)² - k(2) - 18 = 0

= 5(4) - 2k - 18 = 0

= 20 - 18 - 2k = 0

= 2 - 2k = 0

= -2k = -2

= k = -2/-2

= k = 1

value of k is 1.

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