If x+√2 is a factor of kx2-√2x +1 tgen find tge value of k
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Answer:
This is a question of polynomial and also quadratic.
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k = -3/2
Step-by-step explanation:
Given:
x + √2 is a factor of kx²-√2x + 1
To find:
The value of k
Solution:
As x +√2 is a factor.
So, x +√2 = 0 ⟹ x = - √2
Now, Putting the value of x in equation,
kx² - √2x + 1
or, k(-√2)² - √2(-√2) +1 = 0
or, k(2) + 2 + 1 = 0
or, 2k + 3 = 0
or, 2k = -3
or, k = -3/2
Therefore, the required value of k is -3/2.
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