Question

If x-2 is a factor of p(x), then find the value of a, where p(x) is x³-2ax²+ax-1​

Answer 1

Answer:

the zero of the polynomial of x-2 is 2.

so,x=2

p(x)=0

put the value

p(x)=x³-2ax²+ax-1

p(2)=2³-2a2²+a2-1

0=8-8a+2a-1

0=7-6a

6a=7

a=7/6

I think this is helpful

Answer 2

Step-by-step explanation:

above is answer

so please copy that