If x+2 is a factor of p(x), then m=Single choice.
p (x) = x² +mx + 14
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Given x+2 is a factor of x2+mx+14
Let p(x)=x2+mx+14
we know that if x−α is a factor of p(x) then p(α)=0
then
p(−2)=0
(−2)2+m(−2)+14=0
4+14−2m=0
2m=18
m=9
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