if (x-2) is a factor of p(x) x2+4x+k find the value of K.
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Answered by
1
x-2 is a factor, so p(2) = 0
p(2) = 2^2 + 4(2) + k
0 = 4 + 8 + k
k= -12
p(2) = 2^2 + 4(2) + k
0 = 4 + 8 + k
k= -12
Answered by
0
(x-2) is a factor so remainder is 0=p(2)
p(2) =(2) ^2+4(2) +k
0=4+8+k
0=12+k
k=-12
p(2) =(2) ^2+4(2) +k
0=4+8+k
0=12+k
k=-12
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