if (x-2) is a factor of polynomials x^2-3x+5a, find the value of a
Answers
Answered by
1
Answer:
Given that (x−2) is a factor of x
3
−3x+5a
⇒ Remainder =0
x
2
−x−2
(x−2))x
3
−3x+5a
x
3
−2x
2
____________
0−x
2
+5a
−x
2
+2x
____________
0−2x+5a
−2x+4
____________
+(5a−4)
____________
⇒x
3
−3x+5a=(x−2)(x
2
−x−2)+(5a−4)
Remainder =5a−4
but it should be zero for (x−2) to be a factor.
⇒5a−4=0
a=
5
4
(x−2) will be a factor if a=
5
4
.
Answered by
2
Answer:
hope this helps
Step-by-step explanation:
i put a proof too to help you understand
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