Math, asked by Raghbendra, 1 year ago

If x-2 is a factor of
 {x}^{3}   + a {x}^{2}   + bx + 16
than a-b-6=0 . find the value of a and b

Answers

Answered by Kamlesh1128
0
A=6 and B=0. Please check out the answer and comment here.

Raghbendra: how
Raghbendra: can you explain it
Kamlesh1128: the answer is correct?
Raghbendra: how please explain by solving accordingly to question
Kamlesh1128: x-2 is a factor. therefore x=2. putting value in x^3 + ax^2 + bx + 16 we get (2a+b=12)........eq1.....................and a-b-6=0, therefore x-b=6..eq1......... Use elimination method and u will get the answer
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