Question

If x-2 is a factor of the polynomial 3x³-7x²+kx-16, then the value of ‘k’ is​

Answer 1

hope this solution helps u !.....

the value of k = 24

Answer 2

Answer:

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Step-by-step explanation:

zero of x-2=2.

p(x)= 3x^3-7x^2+kx-16

p(2)= 3(2)^3-7*(2)^2+k(2)-16

as it already given p(2)=0

0 = 24-28+2k-16

0 = -4-16+2k

0 = --20+2k

20/2=k

10=k

k=10.....answer

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