Question

If (x-2) is a factor of the polynomial x³-6x²+ax-8, then the value of a is
​

Answer 1

Answer:

6

Step-by-step explanation:

if x-6 is factor of given equation so the value of x satisfying the equation

on putting x = 6 in equation we get a =6

.

ĄŸÛŚH

Answer 2

Step-by-step explanation:

Given: If $(x - 2)$ is a factor of polynomial ${x}^{3} - 6 {x}^{2} + ax - 8$

To find: Find value of a.

Solution:

Tip: Apply factor theorem.

If $(x - a)$ is a factor of p(x), then

$p(a) = 0$

Step 1: Find zero of factor.

$x - 2 = 0$

$\bf x = 2$

Step 2: Calculate $p(2)$ and put $p(2) = 0$

Let the polynomial is $p(x)$

${(2)}^{3} - 6 {(2)}^{2} + a(2) - 8 = 0$

$8 - 24 + 2a - 8 = 0$

$2a = 24$

or

$a = \frac{24}{2}$

$\bf a = 12$

Final answer:

Value of a is 12.

Hope it helps you.

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