Question

If (x-2) is a factor of (x-1)^(6)-(2x+3k) then the value of k is​

Answer 1

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(x-2) is a factor of the equation

(x-2)=0

x=2

$f(x) = {(x - 1)}^{6} - (2x + 3k)$

$f(2) = (2 - 1) {}^{6} - (2 \times 2 + 3k) \\ 0 = {1}^{6} - (4 + 3k) \\ 4 + 3k = 1 \\ 3k = - 3 \\ k = - 1 \: \: ans \: \:$

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