-If x + 2 is a factor of
(x + 1)⁷+ (2x + K)³, K being real then
K
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1
Answer:
f(x)=(x+1)
7
+(2x+k)
3
if (x+2) is a root then placing x=−2,f(x)=0
∴f(x)=0(−2+1)
7
+(2x(−2)+k)
3
(−4+k)
3
=−1 ⇒−4+k=−1
k=3
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