If (x-2) is a factor of x^2-ax+4 then the value of a
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Answered by
1
Answer:
if x-2 =0
x=0+2
x=2
now insert x =2 in equation
x^2 -ax+4=0
2^2 - a×2 +4=0
4-2a +4=0
8-2a =0
8=2a
8/2=a
4=a
theredore the value of a is 4
Answered by
0
Answer:
(x-2)^2 = x2-4x+4
compare this with Qn
- 4x=-ax, a=4
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