If (x-2) is a factor of x^2+ax+b and x^2+cx+d then b-d/c-a =
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Answer:
x=2
substitute the value in equation
2^2+2a+b=0
4+2a+b=0
2(2+a)+b=0
2+a+b=0
a+b=-2
second equation
x^2+cx+d=0
2^2+2c+d=0
4+2c+d=0
c+d=-2 a=a,b=a+2,c=c,d=c+2
a+2-c+2/c-a
a-c+4/c-a
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