Question

If (x-2) is a factor of (x^3+ 3qx-2q) then the value of ‘q’ is. ​

Answer 1

Answer:

$(x - 2) = 0$

$x = 0 + 2$

$x = 2$

Since x is the zero of the polynomial.

So,

$p(x) = {x}^{3} + 3qx - 2q$

Put the value of

$x = 2$

therefore,

$p(2) = {2}^{3} +( 3q \times 2) - 2q \: = 0$

$= 8 + 6q - 2q = 0$

$= 8 + 4q = 0$

$= 4q = - 8$

$= q = \frac{ - 8}{4}$

$= q = - 2$

Hence the value of q is -2

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