If x-2 is a factor of x^3-5x^2+ax-7 then find the value of 'a'
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Answer:a=19/2
Step-by-step explanation:
by factor theorem,
if (x-2)is a factor of p(x) then p(2)=0
so,
p(2)=(2)^3-5(2)^2+a(2)-7=0
8-20+2a-7=0
-19+2a=0
2a=19
a=19/2
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