If (x-2)is a factor of x^3+ax^2+bx+16 and b=4a,find the value of a and b
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179
Given,
x-2 is a factor of x³+ax²+bx+16
⇒2 is the zero of polynomial p(x)=x³+ax²+bx+16
⇒p(2)=(2)³+a(2)²+b(2)+16
⇒0=8+4a+2b+16
Given,b=4a
⇒0=8+4a+2(4a)+16
⇒0=8+12a+16
⇒12a= -24
⇒a=(-24)/12
⇒a= -2
b=4a
⇒b=4(-2)
⇒b= -8
value of a is -2 and b is -8
Hope it helps u:-)
x-2 is a factor of x³+ax²+bx+16
⇒2 is the zero of polynomial p(x)=x³+ax²+bx+16
⇒p(2)=(2)³+a(2)²+b(2)+16
⇒0=8+4a+2b+16
Given,b=4a
⇒0=8+4a+2(4a)+16
⇒0=8+12a+16
⇒12a= -24
⇒a=(-24)/12
⇒a= -2
b=4a
⇒b=4(-2)
⇒b= -8
value of a is -2 and b is -8
Hope it helps u:-)
lekhahasa:
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I think it is linear equation
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