Question

if x-2 is a factor of x^5-3x^4-ax^3+3ax^2+2ax+4 find the value of a​

Answer 1

Answer: 3/2

Step-by-step explanation:

Given f(x) = x^5 - 3x^4 - ax^3 + 3ax^2 + 2ax + 4.

Given g(x) = x - 2.

By the remainder theorem, 

x - 2 = 0

x = 2.

Plug x = 2 in f(x), we get

f(2) = (2)^5 - 3(2)^4 - a(2)^3 + 3a(2)^2 + 2a(2) + 4 = 0

      = 32 - 48 - 8a + 12a + 4a + 4 = 0

      = -16 + 4 + 8a = 0

      = -12 + 8a = 0

     8a = 12

      a = 12/8

      a = 3/2.

Therefore the value of a = 3/2.

Answer 2

Answer:

Step-by-step explanation:

x =2 satisfies the equation

$32-3 .16-8a+3.4a+4a+4=0\\32-48-8a+12a+4a+4=0\\a=\frac{12}{8} =\frac{3}{2}$