If x-2 is a factor of x^5-3x^4-ax^3+3ax^3+3ax^2+2ax+4, then the value of a is plz explain it step by step urgent
Answer =3/8
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Answered by
0
Answer:
huhujiji
Step-by-step explanation:
thnx
Answered by
2
Step-by-step explanation:
Given f(x) = x^5 - 3x^4 - ax^3 + 3ax^2 + 2ax + 4.
Given g(x) = x - 2.
By the remainder theorem,
x - 2 = 0
x = 2.
Plug x = 2 in f(x), we get
f(2) = (2)^5 - 3(2)^4 - a(2)^3 + 3a(2)^2 + 2a(2) + 4 = 0
= 32 - 48 - 8a + 12a + 4a + 4 = 0
= -16 + 4 + 8a = 0
= -12 + 8a = 0
8a = 12
a = 12/8
a = 3/2.
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